How to measure square footage for a room with odd wall sizes?

[robisc]

I quickly need a formula to measure square footage of floor space for a room with different wall dimensions? I know the sq ft. measurement is width times height, for example a 10 x 10 room would be 100 sq ft. but What I need to know is how to figure a room with many different cuts and differing wall lengths, also there is more than 4 wall, anyone?

 

[YetioDoom]

Break it up into rectangles

 

[robisc]

that would work but there must be a formula right?

 

[Viper GTS]

Originally posted by: robisc
that would work but there must be a formula right?

Sure it's the sum of all the parts you know the formula for.

Viper GTS

 

[Armitage]

Originally posted by: YetioDoom
Break it up into rectangles

Probably need some triangles also.

To the OP - nope , there's no formula for figuring out the square footage of an arbitrarily shaped room vaguely described on an internet forum.

You'll have to do some actual thinking on this one.

 

[Kelemvor]

Basically have to do triangles and figure out the angles and such. Then can get the area of it from that. Sketch it out with th emeasurements and post it somwhere if you need help.

 

[Heisenberg]

Integrate.

 

[Lumathix]

If you sketch it out, and give me some dimensions, I'll digitize it for you. Long as you do it before I get off work

 

[fs5]

Are you serious? This is like middle school geometry.

 

[acemcmac]

Originally posted by: fs5
Are you serious? This is like middle school geometry.

qft

 

[FoBoT]

Originally posted by: Armitage

Originally posted by: YetioDoom
Break it up into rectangles

Probably need some triangles also.

To the OP - nope , there's no formula for figuring out the square footage of an arbitrarily shaped room vaguely described on an internet forum.

You'll have to do some actual thinking on this one.

:laugh:

you forgot to reprimand him for us doing his homework for him

 

[Toastedlightly]

remember, bh/2

 

[robisc]

OK guys this isn't homework but a real world problem, I am adding a room above my garage and want to get the square footage for the size, so all of you that say it is easy then tell me what formula or whatever way to figure it without use of a program or by drawing it out on graph paper,Which I have done BTW, the room size ends up being 523.60 SQ ft. but I still say there must be a way to figure this without doing it the way I did? The walls are sized according to this: 6.4', 16', 5.1', 15.6', 13', 15.6', 5.1', 12.8', 16.8', 3'

 

[Sentinel]

I don't think there is, then again I didn't do so hot in trig.

 

[edro]

You need to draw a picture of the walls if you want to use the rectangle method. If those walls are all in order, we could probably do it.

 

[MrDudeMan]

lol i cant believe you think we can help without a visual aid. oh nevermind, i just got the pic from the telepathic broadband network from your brain's IP.

 

[StrangerGuy]

1. Fill room with water
2. Take note of water used
3. Take the height of the level of water
4. Divide water used with height of water and you get the area!

 

[Cristatus]

Originally posted by: edro
You need to draw a picture of there those walls are if you want to use the rectangle method. If those walls are all in order, we could probably do it.

Wouldn't you need to know the angles of the walls, because for all you know, they could all just be in a slightly straight/curved line, and only the last three walls will complete the room. (Note: I didn't not look at any of the numbers, just assuming things here).

 

[edro]

Here it is if those numbers are in order.

518.96 ft²

If the room is square (probably not), then the last leg is 3.2', equalling 520.24 ft².

 

[mrrman]

I would use a diagram, draw the room out and take the largest rectangle/square that would fit into that area space then add each remaining piece to the total

((XxY)+XXxYY+XXXxYYY+.....) where the 1st bracket is the largest area space and the remaining are additives of the odd portions

 

[loup garou]

This is sad.

 

[Shaftatplanetquake]

Originally posted by: edro
Here it is if those numbers are in order.

518.96 ft²

OP, this guy is trying harder than you are.

You suck.

 

[DaShen]

break into rectangles and triangles. triangles are just the rectangles areas / 2.

if you have a 10x10 with one side with a slant, just measure the triangle distance and subtract that area

100 - area of triangle.

Same with any other thing.

 

[QED]

Originally posted by: robisc
but I still say there must be a way to figure this without doing it the way I did? The walls are sized according to this: 6.4', 16', 5.1', 15.6', 13', 15.6', 5.1', 12.8', 16.8', 3'

No, there is not an easier way to do this without knowing more information, such as the angles between each wall.

I can take two rhombuses (simple four-sided shape with all sides equal in length) with the same dimensions and yet they can have completely different areas.

 

[robisc]

Here it is if those numbers are in order. 518.96 ft² If the room is square (probably not), then the last leg is 3.2', equalling 520.24 ft².

Your diagram is pretty close and the numbers are close to mine.

And for the

OP, this guy is trying harder than you are. You suck.

No, you suck. I already have the dimensions now as mentioned in my last post, I just wondered about an easier way to figure it, guess it can;t be done.

Thanks for all the constructive replies.