How to make a table of values out of something like y=(X+4)^2-12

etalns

Diamond Member
Dec 20, 2001
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Was wondering if anyone could help me out with this and tell me the process of how to make a table of values using this to graph it etc. Would appreciate it a ton, I know how to do it if I have the y-int, and im going from the vertex and attempting to find out what is in the rest of the graph. But not from just using the y = a(X-p)q format.
 

felixlee

Member
Jan 8, 2000
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hint: you don't need to make a table of values at all.

if you know how to draw the graph for y=x^2, you should be able to draw y=(X+4)^2-12 easily.
 

etalns

Diamond Member
Dec 20, 2001
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I just pulled that one out of my head, I usually get alot harder ones.

and I need to do it by hand, not permitted to use a calculator for these ones.
 

crystal

Platinum Member
Nov 5, 1999
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Pick a value for one of the variable. Solve it for another variable. List those values in a table. BTW, doesn't matter what values you pick for the first one.
 

XZeroII

Lifer
Jun 30, 2001
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y=(X+4)^2-12

put 0 in for X and solve. You get Y = 4
put 1 in for X and solve. You get Y = 13
put 2 in for X and solve. You get Y = 24

table would look like

X........Y
---------
0........4
1........13
2........24

easy as that.
 

Shelly21

Diamond Member
May 28, 2002
4,111
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what Xzero said.. and then plot those values on a graph paper (if they still sell them....) The more 'dots' you have the better 'picture' you can see.
 

kherman

Golden Member
Jul 21, 2002
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Originally posted by: Qosis
I just pulled that one out of my head, I usually get alot harder ones.

and I need to do it by hand, not permitted to use a calculator for these ones.

Depending what you need to do this for, you might have to calculate asymptotes, mins, means, etc.

For the format you gave, it should be a linear relationship, so you just have to solve y for two values of X and draw a line with a strait edge.

curved graphs require more points.