It's not that simple. You calculations would be correct if power lines were DC but of course power lines are AC. power = voltage * current but both voltage and current are varying. So what you have to do is do a time integral of current draw over the course of 1 sine or cosine AC cycle. And power draw varies over this time period because of ohms's law. Plus it's even more difficult than what I've said because I don't think a PS reacts nice and linearly (after all, it's a switching power supply).states that it draws 8A @120V or 5A at 240V. That calculates to 960W or 1200W respectively (power = voltage * current). Then the efficiency of the supply is useful / cost, in this case 380W / 960W (1200W) which gives you 39.5% (31.7%.)
Originally posted by: zephyrprime
It's not that simple. You calculations would be correct if power lines were DC but of course power lines are AC. power = voltage * current but both voltage and current are varying. So what you have to do is do a time integral of current draw over the course of 1 sine or cosine AC cycle. And power draw varies over this time period because of ohms's law. Plus it's even more difficult than what I've said because I don't think a PS reacts nice and linearly (after all, it's a switching power supply).states that it draws 8A @120V or 5A at 240V. That calculates to 960W or 1200W respectively (power = voltage * current). Then the efficiency of the supply is useful / cost, in this case 380W / 960W (1200W) which gives you 39.5% (31.7%.)
Originally posted by: boi
I bought an electricity meter that plugs into the wall outlet and I measured my computer and it uses about 850watts of electricity under load. I am using an Enermax 431w power supply. It all depends on what type of components you have in your computer.
P4 3.0GHz
1 7200RPM HD
2 CD Drives
Radeon 9700 Pro
Audigy1 Sound Card