How does one find the anti-derivative of (square root of 3x)?

[manlymatt83]

Anyone know?

 

[ColdFusion718]

I'm going to take a wild guess and say it is

2/3*sqrt(3) * x^(3/2) + C


sqrt(3*x) = sqrt*3) * sqrt(x)

so it's sqrt(3) * integral (sqrt(x) = sqrt(3) * integral (x^(1/2))

= sqrt(3) * x^(1/2+1)/(1/2+1) = 2/3*sqrt(3) * x^(3/2) + C...

 

[Soccer55]

I didn't check ColdFusion718's work, so it could be correct, but I'll give you a hint anyway: sqrt(3x) = sqrt(3)*sqrt(x). Now, try finding the anti-derivative of sqrt(3)*sqrt(x).

-Tom

 

[ColdFusion718]

Didn't I already give that hint on the 3rd line of my reply? hehe.

 

[Howard]

2/3 * sqrt[3] * x^(3/2)

?

 

[Soccer55]

Originally posted by: ColdFusion718
Didn't I already give that hint on the 3rd line of my reply? hehe.

I said that I didn't check the work

-Tom

 

[effowe]

Always view square root problems as whatever to the 1/2, in your case, (3x)^(1/2). This will make things much easier.

 

[ArJuN]

I skimmed everyone elses work, but would 2/9(3x)^(3/2) work?

 

[George P Burdell]

Why won't people do their own homework? 404, teh integrity not found

 

[Hacp]

I hate math so much .

 

[racolvin]

anti-derivative? is that like anti-matter, only more concentrated?

I never got past algebra II and some trig and that was MANY years ago, so I dunno what the heck you're talking about