G gplanet Senior member Jan 5, 2002 729 0 0 Sep 25, 2002 #1 I'm trying to solve this problem: y'' + t(y')^2 = 0 i got up to: v' + tv^2 = 0 but i don't know what to do now! any help? thank you in advance
I'm trying to solve this problem: y'' + t(y')^2 = 0 i got up to: v' + tv^2 = 0 but i don't know what to do now! any help? thank you in advance
NutBucket Lifer Aug 30, 2000 27,179 649 126 Sep 25, 2002 #2 This was so two quarters ago. Translation: I don't remember anymore
A Alphathree33 Platinum Member Dec 1, 2000 2,419 0 0 Sep 25, 2002 #3 Somebody tell me where the V came from! Are we magically supposed to assume that y is position and V is velocity? Tell us a bit about it...
Somebody tell me where the V came from! Are we magically supposed to assume that y is position and V is velocity? Tell us a bit about it...
O Orsorum Lifer Dec 26, 2001 27,631 5 81 Sep 25, 2002 #4 If you could quote the entire problem, it would be helpful.
O Orsorum Lifer Dec 26, 2001 27,631 5 81 Sep 25, 2002 #5 Originally posted by: Alphathree33 Somebody tell me where the V came from! Are we magically supposed to assume that y is position and V is velocity? Tell us a bit about it... Click to expand... Means that acceleration is being expressed as a function of position, or vice versa... neither are known. Ugh.
Originally posted by: Alphathree33 Somebody tell me where the V came from! Are we magically supposed to assume that y is position and V is velocity? Tell us a bit about it... Click to expand... Means that acceleration is being expressed as a function of position, or vice versa... neither are known. Ugh.
A Alphathree33 Platinum Member Dec 1, 2000 2,419 0 0 Sep 25, 2002 #6 Just remember F = ma and you can't push a rope.
G gplanet Senior member Jan 5, 2002 729 0 0 Sep 25, 2002 #7 sorry for not being clearer v = y' i just substituted it it has nothing to do with physics