How do I find out someone's IP from an e-mail sent to me?

[Nocturnal]

Where would I find the header information?

I'm using Outlook XP.

TIA

 

[mjquilly]

view->options

 

[RossMAN]

Look for the view header option.

 

[minendo]

Right click the email in the inbox. Choose options.

 

[Nocturnal]

Return-Path: <xxx@xxx.com>
Received: from xxx@xxx.com ([4.7.227.242]) by mm-mp3.bizmailsrvcs.net
(InterMail vM.5.01.06.05 201-253-122-130-105-20030824) with ESMTP
id <20031106001656.PXTN1786.mm-mp3.bizmailsrvcs.net@xxx@xxx.com>
for <xxx@xxx.com>; Wed, 5 Nov 2003 18:16:56 -0600
Reply-To: <xxx@xxx.com>
From: "XXX" <xxx@xxx.com>
To: "08 XXX" <xxx@xxx.com>
Subject: kiosk
Date: Wed, 5 Nov 2003 14:16:33 -1000
Message-ID: <ABEPLCPEBIGDOAHOBKJBOEDACLAA.>
MIME-Version: 1.0
Content-Type: multipart/related;
boundary="----=_NextPart_000_012D_01C3A3A7.6A59ECD0"
X-Priority: 3 (Normal)
X-MSMail-Priority: Normal
X-Mailer: Microsoft Outlook IMO, Build 9.0.2416 (9.0.2910.0)
Importance: Normal
X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2727.1300
________________________________________________________________

Where is the IP in that e-mail header?

 

4.7.227.242 I think.

 

[Nocturnal]

Originally posted by: jumpr
4.7.227.242 I think.

Thanks.

 

[Aves]

4.7.227.242

 

[minendo]

Originally posted by: jumpr
4.7.227.242 I think.

Correct.

 

[MrYogi]

IP Address 4.7.227.242 resolves to:
hnllhi1-ar6-4-7-227-242.hnllhi1.dsl-verizon.net

 

[DannyBoy]

Originally posted by: MrYogi
IP Address 4.7.227.242 resolves to:
hnllhi1-ar6-4-7-227-242.hnllhi1.dsl-verizon.net

Sounds about right 😛