Help with EE homework

tontod

Diamond Member
Oct 12, 1999
3,244
0
71
I just started taking a EE class in op amps. Its been a while since I have last used this material, and I have gotten rusty. If any resident EE's can help me out, that would be great. I need help on the 1st and 3rd problem :

Text
 

dighn

Lifer
Aug 12, 2001
22,820
4
81
just remember that: v- ~= v+ and input z ~= infinity and the problems shouldn't be too hard to solve
 

tontod

Diamond Member
Oct 12, 1999
3,244
0
71
Ok, vp=vn, but not zero, right? And the direction of current flow is towards Vo?
 

dighn

Lifer
Aug 12, 2001
22,820
4
81
Originally posted by: tontod
Ok, vp=vn, but not zero, right? And the direction of current flow is towards Vo?

well since the op amps here do not have gain, i guess you should assume ideal op amp, so vp - vn = 0

yes current towards vo
 

tontod

Diamond Member
Oct 12, 1999
3,244
0
71
Originally posted by: dighn
Originally posted by: tontod
Ok, vp=vn, but not zero, right? And the direction of current flow is towards Vo?

well since the op amps here do not have gain, i guess you should assume ideal op amp, so vp - vn = 0

yes current towards vo

Thanks. Going by those assumptions, I am getting -1V for Vp and Vn, and 3V for Vo for the 1st problem. Does that look right?
 

dighn

Lifer
Aug 12, 2001
22,820
4
81
well actually i get -5v for vout becaues current is going from vn -> vo so it's vn - vo = 4v
 

tontod

Diamond Member
Oct 12, 1999
3,244
0
71
Originally posted by: dighn
well actually i get -5v for vout becaues current is going from vn -> vo so it's vn - vo = 4v

Oh, you get -5 for Vo, by adding -1 with -4? With -1 being Vn and -4 being the drop across the 4k ohm resistor?
 

dighn

Lifer
Aug 12, 2001
22,820
4
81
well the current is going from vn to vo, so vn is + and vo is -. so using ohms law you get

(vn - vo)/4k = 1ma =>
vn - vo = 4v =>
vo = vn - 4v | vn = -1 so vo = -5
 

tontod

Diamond Member
Oct 12, 1999
3,244
0
71
Originally posted by: dighn
well the current is going from vn to vo, so vn is + and vo is -. so using ohms law you get

(vn - vo)/4k = 1ma =>
vn - vo = 4v =>
vo = vn - 4v | vn = -1 so vo = -5

Ah ok, I made a mistake in that I thought vn-vo=-4V, I just had my signs switched, I did get vn=-1 correctly then. Thanks for your help dighn.
 

tontod

Diamond Member
Oct 12, 1999
3,244
0
71
Going by the same logic, for the last problem, vn-vo=3v, vn=vp=vo*(2/5)? Substituting and solving I get vo=-5V. Does that look right?