Help with converting into polar form

[Techie333]

I know this may sound dumb, but my brain is just not working right now. How would I covert the following into polar form i.e. Ae^(j@), where @ = degrees.

2/(-5+j10)

EDIT: PROBLEM SOLVED, THANKS DIGHN!

 

[maximus maximus]

http://www.ticalc.org/archives/files/fileinfo/301/30191.html

 

[Techie333]

Originally posted by: maximus maximus
http://www.ticalc.org/archives/files/fileinfo/301/30191.html

Sorta cheating, eh? I would like to learn the genuine way of doing it.

 

[dighn]

multiply that by (-5-j10)/(-5-j10) to convert it into disctinct real and img components. A is the magnitude of that (use pythagoras), and angle is just atan(img/re) - you get of course two angles, just use the sign of the img component (0-pi for +, pi-2pi for -)

 

[Techie333]

Originally posted by: dighn
multiply that by (-5-j10)/(-5-j10) to convert it into disctinct real and img components. A is the magnitude of that (use pythagoras), and angle is just atan(img/re) - you get of course two angles, just use the sign of the img component (0-pi for +, pi-2pi for -)

THanks a lot! I figured it out!

 

[klah]

good for you

 

[quakefiend420]

Originally posted by: klah
good for you

you bumped a 10 hour old thread just to say this? 😕

postcount++? 😛