• We’re currently investigating an issue related to the forum theme and styling that is impacting page layout and visual formatting. The problem has been identified, and we are actively working on a resolution. There is no impact to user data or functionality, this is strictly a front-end display issue. We’ll post an update once the fix has been deployed. Thanks for your patience while we get this sorted.

Help me with my electronics homework...

I know it has something to do with a different polarity on the emitter and collector but I cannot for the life of me remember what it is. (This is electronics 12)
 
Initials say it all. Those are both BJTs. One is made with n-type collector and emitter with a p-type base, the other has p-type collector and emitter with an n-type base.
 
BJT = Collector - Base - Emitter

CBE
pnp
npn

One has the C&E doped w/ a group V element and the other with a group III
 
iirc,

with the pnp, the b-e junction is forward biased and is reversed biased in the npn.

basically in a pnp you have current going from the e to the c and in a npn from c to e;


i think >_> ; c - collection; b - base; e - emitter
 
Originally posted by: dowxp
iirc,

with the pnp, the b-e junction is forward biased and is reversed biased in the npn.

basically in a pnp you have current going from the e to the c and in a npn from c to e;


i think >_> ; c - collection; b - base; e - emitter

Now are we talking about 'real' current or the bastardized current that all EE's gotta follow.
 
NPN transistors have 2 n's and one p, while pnp transistors have 2 p's and one n. NPN's also taste better.
 
Back
Top