Help me out with this Problem!!!

[asianmusketeer]

There are 12 balls and 1 of the ball is either weight more or less than the rest. You can balance the balls on a balance 3 times and tell which one is the less or more weight ball.

 

[Ace69]

Ummmmmm...........I will get back with you on that one..

 

[MrCraphead]

I'm not quite sure what you mean, could you rephrase the question?

 

[asianmusketeer]

I have 12 balls. 11 out of the 12 are the same weight. 1 out of the 12 is either weight more or less than the the 11. You have 3 chance on a balance to figure out the one that is different from the 11 ballz. Luck don't count.

 

[loogie]

here

 

[mztykal]

You have 12 balls. Out of the 12 balls 11 will weigh the same with 1 weighing more than the others. You have 3 chances to weigh 3 different balls on a balance in order to find out which one it is.

Is that what you mean?

 

[Ace69]

<< here >>

Naughty, naughty, someone didn't check the back posts. :Q

 

[MrCraphead]

hehe, well, assuming that you could put however many balls on the scale at one time as you wanted, it's just as Teckmaster said in the old thread that loogie posted:

&quot;The first weighing you put 6 on one side and six on the other

Second weighing - whichever six was heavier break down and put 3 on one side and 3 one the other

Third weighing - whichever side was heavier put one ball on each side and see which side is heavier. If both are the same then the third ball is the odd ball&quot;

EDIT: Actually, I suppose it's a bit more complicated than that.....but hell, that old thread is freakin' long and I don't really wanna know the answer THAT bad.

 

[axelfox]

Man, if I had 12 balls, I dunno how i would walk.

 

[gooseman]

I only have two, can't help you. Sorry.

 

[Howard]

axelfox - Better limber up those legs!

 

[goodoptics]

the solution

 

[MrCraphead]

whoa......nice. very indepth explanation....

 

[Delusion2001]

lol to ace69