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help in calculating data transfer rate in bps...

M

masked1

Senior member
If a signal with a baud rate of 2400 and 8 signal levels, what is the maximum data transfer rate in bps??
 
You want to know how many bits you can transfer per second. Now, you know you transmit data 2400 times per second, each of those data being from a set of 8 possible.

How many bits are needed to encode eight different numbers?
 
Ah come on. You're lacking the most basic basics of math, binary math to be precise, bring this to a forum clearly labelled "High Tech", so what do you expect? If you can't do a log2(8) or can't figure out that this is what you need to do, then please get your math book out. As I said right at the start, this here really isn't the Homework Channel.
 
While it's amusing to see a thread with really only 2 posters going back and forth.... 😉

2400 times per second, you send one of 8 values. How many bits of information can be represented by 8 values? (Peter has been trying to get you to solve that one... you can verify your answer by doing 2*2 however many times... 3 would be 2*2*2) Once you figure that out, you know that 2400 times per second, you send that many bits.

You should really learn to use google. The second result I got searching for "baud" was:
http://www.webopedia.com/TERM/B/baud.html
 
*bangs forehead on desk*

log2(8)=3, so much is correct. Now you know how many BITS you send in a single transmission. How many transmissions per second do you have, and how many bits per second does that give you?

baud, btw, are transmissions per second.
 
This is one of those questions that I have no idea about but has now sparked my interest...but looking into it more is this how you figure it out ?


the baud rate is how much data is moved in one second = 2400

every second there are 8 bits per baud ??? (not sure if this is right)

so the modem would be transfering bps at 2400 * 8 = 19200 ?


not sure if I am way off base but it was worth a shot....

if anyone could give the right answer I can stop thinking about this 🙂 and move onto other interesting topics lol

leeland
 
You are moving one of eight different symbols per baud. That's not eight bits. Eight bit would let you have 256 different symbols.
 
Originally posted by: Peter
You are moving one of eight different symbols per baud. That's not eight bits. Eight bit would let you have 256 different symbols.
Click to expand...

Oh I got you....so if the baud rate is 2400 and you move 3 bits per baud then the bps second is

2400 * 3 = 7200
 
Originally posted by: DustBunny
holy freaking crap that site is hilarious!
Click to expand...

I found this one very funny for some reason


Customer: "I was wondering if this thing had a fan belt or something in it."

Me: "Sorry, a fan belt?"

Customer: "Yeah, it's getting slower each time I start it in the morning, and I wondered if there was a fan belt or drive shaft that might be slipping."
 
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