I'm taking the second semester of a non-calculus based physics class (mostly cuz it's been four years since I've taken calc), and have a question on one of the assigned problems. Being that it's due tomorrow, I can't exactly go in for help any time before then... Anyway, here it is:
The figure below (seen here) shows a vertically orientated loop in a 1T horizontal magnetic field. The loop is 20cm x 20cm, has a mass of 10g, and a resistance of 0.01ohms, and is halfway through the field. The loop is released from rest.
a) Will the loop fall with constant speed or constant acceleration?
b) How long will it take the loop to leave the field? How does this compare to the time it would take the loop to fall the same distance in the absence of a field?
The magnetic force on the loop ends up being perpendicular to the field, pointing towards you if the field is pointing directly right. That was easy enough to figure out using the good ole right hand rules. I'm wondering if that component of force affects the loops motion in the y-direction being that the force acts in the x-direction. Anyway - any insight you have to this problem would be greatly appreciated. Thanks in advance!
- Eric
The figure below (seen here) shows a vertically orientated loop in a 1T horizontal magnetic field. The loop is 20cm x 20cm, has a mass of 10g, and a resistance of 0.01ohms, and is halfway through the field. The loop is released from rest.
a) Will the loop fall with constant speed or constant acceleration?
b) How long will it take the loop to leave the field? How does this compare to the time it would take the loop to fall the same distance in the absence of a field?
The magnetic force on the loop ends up being perpendicular to the field, pointing towards you if the field is pointing directly right. That was easy enough to figure out using the good ole right hand rules. I'm wondering if that component of force affects the loops motion in the y-direction being that the force acts in the x-direction. Anyway - any insight you have to this problem would be greatly appreciated. Thanks in advance!
- Eric