A mixture of .10 mol of NO, .050 mol of H2, and .10 mol of H2O is placed in a 1.0-L vessel at 300 K. The folloowing equilibrium is established:
2NO(g) + 2H2(g) <-> N2(g) + 2H2O (g)
At equilibrium PartialPressureNO = 1.53 atm
Calculate the equilibrium partial pressures of H2, N2, and H20
The answer is in the back of the book, but I dont know how they got that answer
Help is appreciated
2NO(g) + 2H2(g) <-> N2(g) + 2H2O (g)
At equilibrium PartialPressureNO = 1.53 atm
Calculate the equilibrium partial pressures of H2, N2, and H20
The answer is in the back of the book, but I dont know how they got that answer
Help is appreciated