Grrr stupid physics exam

Deeko

Lifer
Jun 16, 2000
30,213
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81
We had our first exam in physics II....focus on simple harmonic motion, damped SHM, waves, waves along strings, sound waves & sound wave intensity thus far. We VERY briefly touched on youngs modulous, stress/strain and whatnot, to lead into bulk modulous, for the sound stuff. Well, turns out ther was absolutely nothing about sound on the exam, and 25% of the grade was a youngs modulous question, which I of course didn't study very much.
Awesome.
 

Deeko

Lifer
Jun 16, 2000
30,213
12
81
Originally posted by: dopcombo
hmm.... youngs = stress/strain?

hehe :p

haha...yes i realize this now after reading in the book...we were giving lengh & radius of a rod, force exerted, and Y, and asked to find stress, strain, and length changed...could have been fairly easy, had i known the equations at the time
 

Deeko

Lifer
Jun 16, 2000
30,213
12
81
how about this question....

pendelum is hanging from a car, length L with mass M, car is traveling with velocity V around a circle radius R

we were asked to find the frequency...since w = sqrt(g/L) and f = w/2pi, did i need to use M, V, or R? i couldn't really find anywhere to put them.
 

dighn

Lifer
Aug 12, 2001
22,820
4
81
Originally posted by: Deeko
how about this question....

pendelum is hanging from a car, length L with mass M, car is traveling with velocity V around a circle radius R

we were asked to find the frequency...since w = sqrt(g/L) and f = w/2pi, did i need to use M, V, or R? i couldn't really find anywhere to put them.

centripetal acceleration would mean the equivalent g would be higher (pythagorean sum of downwards g and outwards centripetal g)
 

Deeko

Lifer
Jun 16, 2000
30,213
12
81
Originally posted by: dighn
Originally posted by: Deeko
how about this question....

pendelum is hanging from a car, length L with mass M, car is traveling with velocity V around a circle radius R

we were asked to find the frequency...since w = sqrt(g/L) and f = w/2pi, did i need to use M, V, or R? i couldn't really find anywhere to put them.

centripetal acceleration would mean the equivalent g would be higher (pythagorean sum of downwards g and outwards centripetal g)

ah....stuff from physics I, which I had over a year ago, and we of course never discussed in class, nor was on any of the homework/practice problems.

excellent.