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GENIUSES NEEDED: Biochem question about glycine!! i can't figure it out...help

Y

Ymmy

Banned
Glycine is normally present in the liver at a concentration of 0.l mM. The Km for glycine for the detoxification mechanism : benzoyl CoA + glycine --> CoA + Hippuric acid is 0.5 mM. Giving glycine at a dose of 5 g per day raises the liver concentration to 1 mM. By what factor is the enzyme speeded up (assuming no change in benzoyl CoA concentration)?


thanks ahead to all you geniuses.
 
I took biochem in college and again at dental school but I was never good at enzyme concentration equations. You probably can just plug the numbers you listed into the henderson haselbach equation to get your answer (I think at aleast). Just reading it it sounds like a factor of ten though.
 
somehow the CoA or Hippuric acid is decreasing. it's probably decreasing since it takes part in another reaction. find that other reaction.

 
Originally posted by: jst0ney
I took biochem in college and again at dental school but I was never good at enzyme concentration equations. You probably can just plug the numbers you listed into the henderson haselbach equation to get your answer (I think at aleast). Just reading it it sounds like a factor of ten though.
Click to expand...

Michaelis-Menton equation and you've got it. You know Km, and V is dependent on the enzyme concentration, which you know. All you need is ratio, so the other terms don't matter. Probably won't be a factor of 10, btw. Michaelis-Menton wasn't linear, last time I checked.
 
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