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Format questions for video conversion

b4u

Golden Member
Hi,

Can anyone please clear up my mind on a basic question?

What is PAL? It's a standard european format (like NTSC is an American/Japan standard).

So is it 16:9 aspect ratio?

I'm reading some info about video capturing, and I know that PAL has a sample rate of 14.769, with active picture width of 52 microseconds, so I'll need 52*14.769 = 768 pixels wide to fully capture the video (side-to-side).

Am I correct? Or not that correct at all?
 
Take this example:


Let's imagine I want to make a DivX/XviD (PAL).

Full PAL TV on a PC gives 52 µs * 14.7692 MHz = 768 pixels, ending with 768x576.

My "SAA7108, Nvidia with a WDM driver" has a capture window of 53.33 µs.

How many PC sized pixels fit in the capture window? 53.33 µs * 14.7692 MHz = 788 pixels. So I will get a 788x576 resolution.

The way I see it, I will get 788-768=20 black pixel border on playback. Am I right so far?


Ok, let's complicate then ...


Resizing:

If I want that, cap high, say 720x576.
However, the card caps only 53.33 µs (fixed), so I need less pixels to make up the difference with the 52 µs a PC needs for correct Aspect Ratio. How many?
(52 / 53.333) * 720 = 702 in total.

So, remove 18 black pixels of my 720x576 cap. I now have 52 µs of info in 702 pixels. Resize the resulting 702x576 to 768x576 or a scaling of it.


That resizing part I don't quite get ... why would I want to do that? And why choose 720x576 to cap?
 
FYI, you can visit dvdrhelp.com for forums that cover this and all sorts of video related topics. Not that it can't be talked about here.... there's just a wealth of information already there.
 
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