for you math geniuses out there...

[GeneValgene]

anyone know if it's possible to convert this summation to a function?

sigma 1/2^(n+1)

for example, for i=3, it would be 1/2 + 1/4 + 1/8 + 1/16

i suck at teh maths...

 

[GodlessAstronomer]

Certainly is.

 

[Regs]

Oh fawk my nose is bleeding again. This has not happened since high school.

 

[SandEagle]

sure glad i took business math instead

 

[maziwanka]

i freaking forget math, but isn't this a geometric series or something. whatever it is, it definitely equals a number

 

[chuckywang]

The summation equates to 1- 1/2^(n+1).

 

[Regs]

Originally posted by: SandEagle
sure glad i took business math instead

I loved that damn class.

 

[Newbian]

The answer is always 42.

 

[GeneValgene]

Originally posted by: chuckywang
The summation equates to 1- 1/2^(n+1).

i dont' think that works 🙁

 

[Unitary]

Originally posted by: GeneValgene
anyone know if it's possible to convert this summation to a function?

sigma 1/2^(n+1)

for example, for i=3, it would be 1/2 + 1/4 + 1/8 + 1/16

i suck at teh maths...

Please be more specific about your question. For example, where does "i=3" come into play in your sum?

 

[TuxDave]

Originally posted by: GeneValgene

Originally posted by: chuckywang
The summation equates to 1- 1/2^(i+1).

i dont' think that works 🙁

How about now?

 

[Oceandevi]

Originally posted by: chuckywang
The summation equates to 1- 1/2^(n+1).

actually its 1- 1/2^^QQ(n+1)(n-1)

 

[GeneValgene]

Originally posted by: Oceandevi

Originally posted by: chuckywang
The summation equates to 1- 1/2^(n+1).

actually its 1- 1/2^^QQ(n+1)(n-1)

what does Q mean?

 

[TuxDave]

Originally posted by: GeneValgene

Originally posted by: Oceandevi

Originally posted by: chuckywang
The summation equates to 1- 1/2^(n+1).

actually its 1- 1/2^^QQ(n+1)(n-1)

what does Q mean?

Wait you're still looking at this thread? You know chuckywang's answer is correct right where n is the end of your summation (or i as in the post I made)

 

[AyashiKaibutsu]

f(x) = i =0 sigma x 1/2^(n+1)

?

 

[dullard]

We are all assuming the summation is over the range n=0,1,2,...,i. If that isn't true, then please correct your orginal post.

Originally posted by: chuckywang
The summation equates to 1- 1/2^(n+1).

While chuckywang's formula does work, I perfer the engineering approach:

1) If i<=3, just do it by hand; it is really, really easy math.
2) If i>=4, then the summation is close enough to 1 that we can just call it 1 for almost all uses.