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Figuring ohm value on resistors

Braxus

Golden Member
Stupid question here... Trying to figure out the ohm value of a reisistor that I have here. Most resistors that I've seen are tan colored with four bands. However, the one I have here has a light blue colored jacket with five color bands. What's the method of cacluating these ones?

Also, any difference between the tan and the blue jacket colored resistors?
 
47 Ohms, "fer sher," the blue is usually a ceramic carbon-film, the brown band (likely to really be "gold" ) is (I believe) 5% (47 Ohms, + / - 5%).

The resistor color code is

Black.............0
Brown...........1
Red...............2
Orange.........3
Yellow...........4
Green...........5
Blue..............6
Violet............7
Grey.............8
White...........9

Standard is two bands for value, the third band is the multiplier, in "Tens" (black = no multiplier(1), brown is X10, red is X100, orange is X1000, etc)

Tolerance: No color = 20%, Silver = 10%, Gold=5% (if it is brown, it probably is a 1% - I don't remember)

Yellow (4), violet (7), black (0), black (no multiplier), brown (tolerance - gold is 5%)


Good Luck

Scott
 
Originally posted by: Braxus
Stupid question here... Trying to figure out the ohm value of a reisistor that I have here. Most resistors that I've seen are tan colored with four bands. However, the one I have here has a light blue colored jacket with five color bands. What's the method of cacluating these ones?

Also, any difference between the tan and the blue jacket colored resistors?


Those are usually precision resistors (<1%). The 5'th colour is the precision.

 
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