Feel like a physics problem, anyone?

Heisenberg

Lifer
Dec 21, 2001
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Ehh...it's some demonic incarnation of conservation of momentum but I'm too tired to see how to do it. Sorry.
 

Heisenberg

Lifer
Dec 21, 2001
10,621
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Originally posted by: CrackaLackaZe
It's a center of mass problem, I'm so pissed...I'm letting this question own me.
Oh yeah, duh. I read the 37.4 as velocity, not displacement.
 

shadow

Golden Member
Oct 13, 1999
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I haven't done physics in over 4yrs, but it seems pretty straightforward, just set up your equations to equal eachother and solve for her mass, you'll find stuff will cancel out. I'm sorry man, I don't believe in giving answers, but after you figure out the right equation it becomes easy.

good luck
 

Bound_Vortex

Member
Feb 6, 2000
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Easiest way to do it is to look at the changes in center of mass. Since Ricardo is the heavier of the two, we will treat his movement as positive and Carmelita's movement as negative.

mRicardo*dRicardo-mCarmelita*dCarmelita = (mRicardo+mCarmelita+mCanoe)*dTotal

70*3.1-x*3.1 = (70+x+27)*.374
217-3.1x = 36.278+.374x
-3.474x = -180.726
x = 52.02 kg = mass of Carmelita
 

CrackaLackaZe

Senior member
Jun 29, 2002
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Originally posted by: Bound_Vortex
Easiest way to do it is to look at the changes in center of mass. Since Ricardo is the heavier of the two, we will treat his movement as positive and Carmelita's movement as negative.

mRicardo*dRicardo-mCarmelita*dCarmelita = (mRicardo+mCarmelita+mCanoe)*dTotal

70*3.1-x*3.1 = (70+x+27)*.374
217-3.1x = 36.278+.374x
-3.474x = -180.726
x = 52.02 kg = mass of Carmelita

I see...thx, I didn't realize that the displacement of the canoe was the change in center of mass.