A child 6 ft tall walks at a rate of 6 ft/sec toward a lightpole that is 22 ft above the ground. At what rate is the length of his shadow (x+y) changing when he is 36 ft (y) from the base of the light.
I got 9/4 ft./sec. Can anyone check?
edit:
steps
\frac{x+y}{22}=\frac{x}{6}
y=\frac{8}{3} \times x
d/dt(y)=d/dt(\frac{8}{3} \times x)
6=8/3 dx/dt
dx/dt=9/4
I got 9/4 ft./sec. Can anyone check?
edit:
steps
\frac{x+y}{22}=\frac{x}{6}
y=\frac{8}{3} \times x
d/dt(y)=d/dt(\frac{8}{3} \times x)
6=8/3 dx/dt
dx/dt=9/4