f(x) = cos(sqrt(sinx)) (I need a quick answer -> but not the "my assignment isn't done and it's due in 5 minutes" kind

[BigToque]

can someone please tell me what the square root of sinx is. I saw it in my textbook before, but I don't have it with me and I can't find it on google. (is it "cos - 1" or "-cos -1" or something similar?)

I'm trying to find the derivitive of f(x).

 

[misle]

You don't need to find what the sqrt of SinX is for that. Just do the derivative.

Re-write the equation like this:
f(x) = Cos ((SinX)^(1/2))

That should make the derivative easier to see.

 

[BigToque]

geez... I knew that

so that means the derivitive of f(x) = cos(sqrt(sinx))

f'(x) = -sin(sinx^1/2)(1/2cos^-1/2)

?

 

[edro]

Don't you have a little formula sheet or something. That's what I used... I don't think it's somethign that you can "work out". I think the answer just is. Too bad I don't know what it is.

 

[misle]

Here's a hint for you.

If F(x) = f(g(x)) then F'(x) = f'(g(x)) g'(x).

 

[BigToque]

Originally posted by: misle
Here's a hint for you.

If F(x) = f(g(x)) then F'(x) = f'(g(x)) g'(x).

Then that is what I have...

 

[conjur]

Originally posted by: Stefan

Originally posted by: misle
Here's a hint for you.

If F(x) = f(g(x)) then F'(x) = f'(g(x)) g'(x).

Then that is what I have now...

Fixed for ya.

 

[BigToque]

lol thanks for the help

 

[silverpig]

You'll never post another integral or derivative question again.

 

[amoeba]

chain rule man, chain rule.

 

[Aves]

Originally posted by: silverpig
You'll never post another integral or derivative question again.

I used that site for differentiation but they charge you for the step by step solutions for integration.

I suppose $15 for 900 solutions isn't that bad. I may have to break down and put up the cash.

 

[silverpig]

Originally posted by: aves2k

Originally posted by: silverpig
You'll never post another integral or derivative question again.

I used that site for differentiation but they charge you for the step by step solutions for integration.

I suppose $15 for 900 solutions isn't that bad. I may have to break down and put up the cash.

Or you could just not pay and get the answer for integration for free sans step by step.

 

[eLiu]

Originally posted by: edro13
Don't you have a little formula sheet or something. That's what I used... I don't think it's somethign that you can "work out". I think the answer just is. Too bad I don't know what it is.

Formula sheet? Uhm...no. It's called the "chain rule." That is, given f(g(x)), the derivative of that expression is: f'(g(x))*g'(x)

-Eric

 

[eLiu]

Originally posted by: edro13
Don't you have a little formula sheet or something. That's what I used... I don't think it's somethign that you can "work out". I think the answer just is. Too bad I don't know what it is.

Formula sheet? Uhm...no. It's called the "chain rule." That is, given f(g(x)), the derivative of that expression is: f'(g(x))*g'(x)

-Eric