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Err Chem help?

M

ManBearPig

Diamond Member
From the following data, calculate the total heat (in Joules) needed to convert 2.966 grams of ice at -8.485 oC to liquid water at 6.409 x 101 oC.

Melting point at 1 atm 0.0 oC
Cwater(s) = 2.09 J/g oC
Cwater(l) = 4.21 J/g oC
delta Hofus = 6.02 kJ/mol

____ joules


how would i do this? any help?

thanks
 
2.966 (2.09) (8.485) + (2.966/18.015)(6020) + (64.09)(4.21)(2.966) = ___ joules.

I think that's right, granted I haven't done thermo stuff for a while.

edited at end.
 
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