erg, math help needed, problem inside...

[brtspears2]

45000/1+r^47 = 630


I get so far...

45000 = 630(1+r^47)
45000 = 630+630r^47
44370 = 630r^47

44370/360 = r^47

70.43 = r^47

Whats next? Did I take the right path?

 

What class is this for? It may clear up what is requested here, 'cuz it hasn't been stated what should the objective is here.

 

[Sephy]

If you're just solving for r, raise the 70.43 to the 1/47 power and you have the answer

 

[Mo0o]

is this algebra 3/4?

 

[GtPrOjEcTX]

1.09474710637

 

[Mo0o]

you can graph y=70.43 and y=r^47 and then find intersection.

 

[GtPrOjEcTX]

which would be 1.09474710637

 

[Mo0o]

well, its better to know how to do it rather than just know the answer

 

[Sephy]

Which is done by taking the 47th root, ie 1/47 power