Electronics Experts: I have a "schematic" for a simple power amplification circuit, round 2

Jeff7

Lifer
Jan 4, 2001
41,596
19
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Awhile ago, I posted this thread. Well I finally got around to trying this, mainly because I have another project involving schematics and making PCB's. I need to figure out if I drew this out right.

Demon-Xanth's instructions were:
Use a LM393 (comparator)

Pin 1: tie a 100 ohm to 1k resistor between it and pin 8, attach the LED to this pin and ground
Pin 2: attach a 1k resistor going to pin 8, and another to pin 4
Pin 3: this is your input
Pin 4: ground
Pins 5, 6, and 7: tie it to pin 4
Pin 8: tie to +5V

From that, I made this:
Schematic pic

LMK if it's anything close to what it should be. If not, don't laugh too hard, or spit carbonated drinks on your computers. :) I probably violated several hundred schematic rules, but hopefully it's understandable.
Thanks goes to ExpressPCB for their freeware programs. (Though the printouts have a grid pattern on, which I can't get rid of - and I need to be without the grid.)
 

xyion

Senior member
Jan 20, 2001
706
0
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well, first off I must say that I have absolutely no idea what this circuit is doing. Every comparator I have designed looks absolutely nothing like this (not saying he's wrong however. More than 1 way to skin a cat). The fact that you are tying everything to +5V and Ground is really what is confusing me.

That said, you seemed to draw out the schematic correctly based on the given instructions, except for pins 5,6, and 7. Why do you have another input there? They should all be grounded (probably because you got a dual opamp ICC).

EDIT: This is how I would design a comparator.
 

Analog

Lifer
Jan 7, 2002
12,755
3
0
From your schematic, the LED is being driven from the 5V rail to ground, so the LM393 is doing nothing.
 

Jeff7

Lifer
Jan 4, 2001
41,596
19
81
Originally posted by: yellowfiero
From your schematic, the LED is being driven from the 5V rail to ground, so the LM393 is doing nothing.

Yes, I see that now. I've got to get some sleep now; I'll look at this again tomorrow morning when I get home from work.
How I got that comparator? I went to the components list in ExpressSCH, and selected the LM393 comparator, and that's what it put onto the work area.
 

Jeff7

Lifer
Jan 4, 2001
41,596
19
81
Ok, I updated the schematic, v1.1 with another resistor - "attach a 1k resistor going to pin 8, and another to pin 4"
...but it's still got the 5V+ -> LED -> Ground problem.
Now that statement there...could that mean, Attach a 1K resistor going to pin 8, and from that point, go to pin 4? Or would that have no effect on the circuit? Guess not - still have the 5V powering the LED directly.
Maybe I need an instructions-rewrite?