Jeff7
Lifer
Alright, so I've got a pellet stove here, and I might be interested in giving it backup power, courtesy of a pure sinewave inverter and a lead acid battery.
Now, I got some figures from my Kill-A-Watt:
10.19KWH over 114 hours. So I guess that means it uses about 89.4 watts per hour, correct?
So assuming a 100% efficient inverter (which won't happen, I know,) that'd mean a battery rated, say 12V @ 7.45A (12 * 7.45 = 89.4), would in theory power this stove for one exactly hour? Assuming a perfect world, that is - I just want to know if my concepts are right here.
I am not sure if there are any weird calculations that need to be done since one is AC (stove) and one is DC current (battery).
Hopefully that made some semblance of sense. I just get the idea that running the stove for a day or so on a battery would need one helluva big battery. Right?
Now, I got some figures from my Kill-A-Watt:
10.19KWH over 114 hours. So I guess that means it uses about 89.4 watts per hour, correct?
So assuming a 100% efficient inverter (which won't happen, I know,) that'd mean a battery rated, say 12V @ 7.45A (12 * 7.45 = 89.4), would in theory power this stove for one exactly hour? Assuming a perfect world, that is - I just want to know if my concepts are right here.
I am not sure if there are any weird calculations that need to be done since one is AC (stove) and one is DC current (battery).
Hopefully that made some semblance of sense. I just get the idea that running the stove for a day or so on a battery would need one helluva big battery. Right?
