Appledrop Platinum Member Aug 25, 2004 2,340 0 0 Oct 30, 2005 #1 hrrm.. just suppose that these points on graphs: A=(7,12) and B=(-3,-12) and C=(14,-5) well.. Show that AC is perpendicular to BC Please show your working, so i know you arent cheating... Go go go!
hrrm.. just suppose that these points on graphs: A=(7,12) and B=(-3,-12) and C=(14,-5) well.. Show that AC is perpendicular to BC Please show your working, so i know you arent cheating... Go go go!
her209 No Lifer Oct 11, 2000 56,336 11 0 Oct 30, 2005 #3 -5-12=-17 14-7=7 -5-(-12)=7 14-(-3)=17 I win
R randal Golden Member Jun 3, 2001 1,890 0 76 Oct 30, 2005 #4 y=mx+b, find the slopes ... something_about_negative_and_how_they_compare ... they're perpendicular. her209 got it, good job
y=mx+b, find the slopes ... something_about_negative_and_how_they_compare ... they're perpendicular. her209 got it, good job
Y Yossarian Lifer Dec 26, 2000 18,010 1 81 Oct 30, 2005 #6 I hate when people write "maths". I even hate myself a little bit for writing it just now.
Random Variable Lifer Aug 10, 2001 10,420 2 0 Oct 30, 2005 #7 AC = (7,-17) BC = (17,7) AC dotted with BC = (7*17) + (-17*7) = 0
D dethman Lifer Oct 12, 1999 10,263 3 76 Oct 30, 2005 #8 Originally posted by: Lonyo Do your own homework. Click to expand...
P PurdueRy Lifer Nov 12, 2004 13,837 4 0 Oct 30, 2005 #9 Originally posted by: Random Variable AC = (7,-17) BC = (17,7) AC dotted with BC = (7*17) + (-17*7) = 0 Click to expand...
Originally posted by: Random Variable AC = (7,-17) BC = (17,7) AC dotted with BC = (7*17) + (-17*7) = 0 Click to expand...