Eh...what did I do wrong on this problem? (math)

Hoeboy

Banned
Apr 20, 2000
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Going over previous exams for the final today and couldn't see why he marked this one wrong. It really bothers me when teachers simply mark something wrong without telling why. The problem states:


Three committees of respectively 4, 3, and 2 people are to be formed. They are to be formed from a group of 12 people. How many ways can this be done if:

a) No person can serve in more than one committee?

My solution : C(12,4) + C(8,3) + C(5,2) = 561

b) A person can serve in any number of committees?

My solution : C(12,4)+ C(12,3) + C(12,2) = 781
 

Hoeboy

Banned
Apr 20, 2000
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Yeah I was tearing my hair out. I knew I did the combinations right but I guess I should have multiplied. Part b is right no?
 

gopunk

Lifer
Jul 7, 2001
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yea looks right to me. but i missed a few points on my final for as-of-yet unknown reasons, so take it with a grain of salt :p
 

Hoeboy

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Apr 20, 2000
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Funny how I was doing the exact same junk in Prob & Stats yet I'm doing so fine in that class compared to this one. I hate the language!