EE people! i need your help!!

Omegachi

Diamond Member
Mar 27, 2001
3,922
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2.41 is practically the same problem, the circuit just looks a little different. its no help.

oh yea, sorry about the junky resolution on the camera, took the pic too close.
 

SuperTool

Lifer
Jan 25, 2000
14,000
2
0
My guess is Req2 =Req1
If R=infinity, Req1=Req2
If R=0, then Req1=2+(2||4) Req2=2+(1||2)+(1||2), so again Req2=Req1.
 

Ranger

Senior member
Oct 9, 1999
206
0
76
I think you are right, there is no current flow between a and b
so the value of R doesn't matter
 

SuperTool

Lifer
Jan 25, 2000
14,000
2
0
well, you have those 2 resistors next to a and b for both cases.
Req1 is 2+(2||4) (the path trhough a has 2 resistors and path through b has 4 resistors)
If R=inf. then Req1 is identical to Req2, because that's as if there was empty space there instead of R.
If R=0, then a=b is same point. then above a, you have 2||1, and below a you have 2||1, and you also have the 2 on the left
so Req2= 2+(2||1)+(2||1)=2+2*(2||1)=2+(4||2)=Req1. That part is simple. your task is to show that between 0-inf, it's equal too.
 

SuperTool

Lifer
Jan 25, 2000
14,000
2
0
Look at it in terms of symmetry.
The voltage between A and B is going to be halfway between the endpoint voltages, due to symmetry, because whatever the actual resistance is, it's pretty obvious that resistance to the top terminal from A is same as resistance from A to the bottom terminal. Same thing for B. So Va=Vb=(Vtop+Vbot)/2, so there isn't going to be any current flow through the resistor I=(Vab)/R =0