Edit: Math questions answered, thx

[Ultima]

Edit:

Thanks for answering my questions, I've got everything I need to know now

 

[BaboonGuy]

use long division

 

[Flyermax2k3]

The answers are:
What and
The fvck
respectively, of course.

Sorry, couldn't resist. I hope someone can give you the real answers, LOL

 

[Nocturnal]

edited for stupidity

 

[minendo]

First one factors to (x-4)(x-1)/(x-1)

Second factors to (2x-3)(x+4)/(x+4)

 

[jacob0401]

x-4
2x-3

You can either factor out the top to see if the top and bottom cancel out or you have to use long division of polynomials. There is an easier way called synthetic division to use instead of long division as well.


Here's a link...

 

[Nocturnal]

Jesus H. Christ I just learned all this crap this past semester and I can't even do the first problem ROFL. School starts Tuesday too oh damn.

 

[Nocturnal]

Originally posted by: minendo
First one factors to (x-4)(x-1)/(x-1)

Second factors to (2x-3)(x+4)/(x+4)

The two (x + 1) in the denominator and the numerator will cancel each other out. The answer will then be (x-4).

The second one, the two (x + 4) cancel each other out as well.

 

[Syringer]

Originally posted by: Ultima
Can anyone give me the solutions to the following problems? I need to help out some kid with radicals but I don't remember exactly how to solve these types:

(x^2 - 5x + 4) / (x - 1)
(2x^2 + 5x - 12) / (x + 4)

Or these:

sqrt(x)
--------------------
sqrt(a) + sqrt(x)


Can someone just show me an example of the solutions to these problems to clue me in?

x^2-5x+4 factors to (x-4)(x-1), so x-1 cancels out leaving you with x-4

2x^2 + 5x - 12 factors to (x+4)(2x-3), x+4 cancels out leaving you with 2x-3

 

[Howard]

DON'T SAY CANCEL! SAY THEY DIVIDE OUT!

 

[Nocturnal]

I think the last problem is you take the denominator and multiply both the numerator and the denom by it. It'll have perfect squares in the end for the denom and a radical + something in the numerator.

 

[Nocturnal]

Originally posted by: Howard
DON'T SAY CANCEL! SAY THEY DIVIDE OUT!

SORRY!

 

[Ultima]

what about the answer to the second one?

Is it:

sqrt(x)
--------------------
sqrt(a) + sqrt(x)

equals:

sqrt(x*a) - x
----------------
a-x

?

 

[Nocturnal]

Sorry, yes your answer is correct.

Or should it be:

sqrt(a) - x
--------------
a - x

 

[Syringer]

That's correct.

 

[Ultima]

Nice, I read some stuff on the net and I remember how to reverse the trinomial now. Actually, I remember writing a calculator program to do it automatically

X^2 + bx + c, will be (x + d) (x + e) where d+e = b, d*e = c

Now it's just the other thing I need to get down

 

[Ultima]

Originally posted by: Syringer
That's correct.

which is?

 

[Ultima]

Originally posted by: Ultima

Originally posted by: Syringer
That's correct.

which is?

I guess mine is, cause I just checked with a calculator by plugging vals into A and X.