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Dumb top question...

A

Armitage

Banned
Watching the top output, my program shows 142MB virt and 105MB res. This is on a machine with 2GB RAM

I assume this means Virtual (swapped to disk) and Resident (RAM). Correct?

So ... I could potentially run this on a machine with only 256MB, since only 105MB is actually in RAM?

Anybody understand how this memory management works? I'm curious why a program that I just started, that has the CPU pegged on an otherwise idle machine would have over half the memory swapped out.


 
VIRT -- Virtual Image (kb)
The total amount of virtual memory used by the task. It includes all code, data and
shared libraries plus pages that have been swapped out.

VIRT = SWAP + RES.
Click to expand...

q: RES -- Resident size (kb)
The non-swapped physical memory a task has used.

RES = CODE + DATA.
Click to expand...
 
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