- Aug 10, 2001
- 10,420
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?d³(Ax+b)f(x)d³x from -8 to +8 = f(-A^(-1)b)/|Det A|
Everything in bold type is a vector. And d is the delta function. Obviously you have to make a substition for Ax+b and then deal with the Jacobian in some fashion.
Everything in bold type is a vector. And d is the delta function. Obviously you have to make a substition for Ax+b and then deal with the Jacobian in some fashion.
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