Do you consider this a challenging chemistry problem?

[archcommus]

It only involves basic ideas and concepts (as in, the first few chapters of any chemistry book), but I still think it's a bit beasty of a problem. The professor disagreed and was surprised so few people in the class got it right. Do you consider this hard for introductory chemistry?

Problem: Consider a 2.1 L, V6 engine that uses gasoline with a chemical makeup of C8H18 (density = .899 g/mL) that, when combusted, produces gases at 450 deg. C and at 1 atm pressure. Using this information, how many microliters of gasoline should be injected into EACH cylnder so that, when combusted, each piston will be fully but not overly extended?

 

[MikeyIs4Dcats]

uhwhut?

 

[statik213]

no

 

[TheGizmo]

Originally posted by: statik213
no

 

[Vegitto]

Originally posted by: archcommus
It only involves basic ideas and concepts (as in, the first few chapters of any chemistry book), but I still think it's a bit beasty of a problem. The professor disagreed and was surprised so few people in the class got it right. Do you consider this hard for introductory chemistry?

Problem: Consider a 2.1 L, V6 engine that uses gasoline with a chemical makeup of C8H18 (density = .899 g/mL) that, when combusted, produces gases at 450 deg. C and at 1 atm pressure. Using this information, how many microliters of gasoline should be injected into EACH cylnder so that, when combusted, each piston will be fully but not overly extended?

Would be a piece of cake if I knew what 1 atm was.. Could you give me 1 atm in Pa or bar?

 

[KLin]

Originally posted by: Vegitto

Originally posted by: archcommus
It only involves basic ideas and concepts (as in, the first few chapters of any chemistry book), but I still think it's a bit beasty of a problem. The professor disagreed and was surprised so few people in the class got it right. Do you consider this hard for introductory chemistry?

Problem: Consider a 2.1 L, V6 engine that uses gasoline with a chemical makeup of C8H18 (density = .899 g/mL) that, when combusted, produces gases at 450 deg. C and at 1 atm pressure. Using this information, how many microliters of gasoline should be injected into EACH cylnder so that, when combusted, each piston will be fully but not overly extended?

Would be a piece of cake if I knew what 1 atm was.. Could you give me 1 atm in Pa or bar?

google conversion

 

[Chaotic42]

Edit: Ah, I see now.

 

[Hyperion042]

Cake.

 

[Vegitto]

Originally posted by: KLin

Originally posted by: Vegitto

Originally posted by: archcommus
It only involves basic ideas and concepts (as in, the first few chapters of any chemistry book), but I still think it's a bit beasty of a problem. The professor disagreed and was surprised so few people in the class got it right. Do you consider this hard for introductory chemistry?

Problem: Consider a 2.1 L, V6 engine that uses gasoline with a chemical makeup of C8H18 (density = .899 g/mL) that, when combusted, produces gases at 450 deg. C and at 1 atm pressure. Using this information, how many microliters of gasoline should be injected into EACH cylnder so that, when combusted, each piston will be fully but not overly extended?

Would be a piece of cake if I knew what 1 atm was.. Could you give me 1 atm in Pa or bar?

google conversion

Goddamn, I have no idea of the length of one piston.. I don't think I can do it..
EDIT: Weight of one piston would be handy, too.
This isn't just chemistry...

 

[simms]

Originally posted by: Vegitto

Originally posted by: archcommus
It only involves basic ideas and concepts (as in, the first few chapters of any chemistry book), but I still think it's a bit beasty of a problem. The professor disagreed and was surprised so few people in the class got it right. Do you consider this hard for introductory chemistry?

Problem: Consider a 2.1 L, V6 engine that uses gasoline with a chemical makeup of C8H18 (density = .899 g/mL) that, when combusted, produces gases at 450 deg. C and at 1 atm pressure. Using this information, how many microliters of gasoline should be injected into EACH cylnder so that, when combusted, each piston will be fully but not overly extended?

Would be a piece of cake if I knew what 1 atm was.. Could you give me 1 atm in Pa or bar?

101325pa
1.01325bar

 

[SVT Cobra]

its easy just use conversion factors

plus you need to know what combustion of a hydrocarbon is going to produce...set up the equation, balance it, then set up your conversion factors

 

[Mark R]

.

 

[Fenixgoon]

i can't do it

don't you need to know the length of a full extension?

 

[Indolent]

Originally posted by: Mark R
.

You dont' need it

when combusted, produces gases at 450 deg. C and at 1 atm pressure

that's all you need. It's not realistic but is probably done to simplify the problem

 

[Indolent]

oops, hit quote instead of edit

 

[Mark R]

Originally posted by: Indolent

Originally posted by: Mark R
.

You dont' need it

Lol. You were fast.

 

[Armitage]

Originally posted by: Fenixgoon
i can't do it

don't you need to know the length of a full extension?

No - you just need the volume of the cylinder when fully extended. You know the total displacement, and you know the number of cylinders.

 

[SilentZero]

Originally posted by: Indolent

Originally posted by: Mark R
.

You dont' need it

when combusted, produces gases at 450 deg. C and at 1 atm pressure

that's all you need. It's not realistic but is probably done to simplify the problem

I wasn't a chem major or minor for that matter, but isn't it easier to convert 1 atm to torr's and solve?

 

[archcommus]

The answer is 44 microliters/cylinder for anyone trying to figure it out.

And you don't need to convert pressure.

 

[SaturnX]

well with a quick calculation, I got 44 mL, not microlitres.... took about 2 lines to calculate, but I definately don't see this as being a difficult question.

--Mark

 

[archcommus]

Originally posted by: SaturnX
well with a quick calculation, I got 44 mL, not microlitres.... took about 2 lines to calculate, but I definately don't see this as being a difficult question.

--Mark

Well obviously it takes more work than that as that's the wrong answer.

I also don't see it as THAT bad. I got it right but was slightly surprised I did.