Do volume levels add up?

[AtomicDude512]

So, I am once again on a case-quieting spree. I want to know if volume level's add up? So does all this:

27Db (Maxtor DiamondMax8)
21Db (Panaflo L1a)
??Db (40mm GPU Fan, I think it's around 35Db)
30-32Db? (Antec TruePower 330w)

equal around 110db? I am confused. But I plan to purchase the Zalman ZM-80AHP for my GPU since when I took it out and put in a video card without a fan the noise dropped quite a bit.

 

[tranceport]

It certianly feels fuller and louder when you have more speakers. However I am not really sure if the db level is any higher. Just more air pressure that the ear senses.

 

[tranceport]

I assume you mean fans though... 🙂

 

[Rio Rebel]

Not at all - my Volcano 9 drowns out all the fans, my speakers, the tv, and my wife's bitching quite nicely. There's not cumulative effect at all.

I especially like the effect of feeling like you're standing in front of a 747 while you play games. It's so cool.

 

[AtomicDude512]

Originally posted by: Rio Rebel
Not at all - my Volcano 9 drowns out all the fans, my speakers, the tv, and my wife's bitching quite nicely. There's not cumulative effect at all.

I especially like the effect of feeling like you're standing in front of a 747 while you play games. It's so cool.

Im going for more of a "hummingbird" sound, thanks though. 🙂

 

[SickBeast]

no, you don't simply "add" the db from each fan to come up with the total. there is a logarythmic calculation to figure it out. generally, if you have 2 noise sources at 35db each, they should add up to ~40db iirc.

 

[SickBeast]

Originally posted by: SickBeast
no, you don't simply "add" the db from each fan to come up with the total. there is a logarythmic calculation to figure it out. generally, if you have 2 noise sources at 35db each, they should add up to ~40db iirc.

<edit: by the way, 110db would be deafeningly loud...like the sound of a harrier jet taking off 🙂>

 

[BA]

In theory, this is how it works.(Of course this neglects the frequency, the case, etc)


Divide all the values by 10.
Raise 10 to the power of whatever you got
add all these up
Take the log
multiply by 10.

So in this case:
10^3.3=1995.3
10^2.1=125.89
10^3.5?=3162.3
10^3.1?=1258.9
------------------------
6542.4

log6542.4=3.82

3.82=38.2

38.2db

 

[Ketchup]

Originally posted by: SickBeast

Originally posted by: SickBeast
no, you don't simply "add" the db from each fan to come up with the total. there is a logarythmic calculation to figure it out. generally, if you have 2 noise sources at 35db each, they should add up to ~40db iirc.

<edit: by the way, 110db would be deafeningly loud...like the sound of a harrier jet taking off 🙂>

I think 110db is the maximum acoustic output of my 400-watt Klipsch's. You couldn't stand it if it was that loud all the time.

 

[Madboy2003]

thx ba
i like it

can u tell me how to consider the case in this ex. ? aprox. ofcourse
just a regular mid tower atx case
how much noise it holds back?

 

[Batman5177]

Originally posted by: BA
In theory, this is how it works.(Of course this neglects the frequency, the case, etc)


Divide all the values by 10.
Raise 10 to the power of whatever you got
add all these up
Take the log
multiply by 10.

So in this case:
10^3.3=1995.3
10^2.1=125.89
10^3.5?=3162.3
10^3.1?=1258.9
------------------------
6542.4

log6542.4=3.82

3.82=38.2

38.2db

String fanNoise = " ";
int dbLevel = 0;
ArrayList list = new ArrayList();

while (!fanNoise.equals(null))
{
System.out.print("Enter fan db level ");
System.out.println();
fanNoise = console.readLine();

if (!fanNoise.equals(null))
{
dbLevel = Integer.parseInt(fanNoise);
list.add(dbLevel);
}

}

for (int i = 0; i < list.size(); i++)
{
list = list/10;
list = Math.exp(10,list);
}

int sum = 0;

for (int i = 0; i < list.size(); i++)
{
sum += int;
}

sum = Math.log(sum);

sum *= 10;

System.out.println("Answer: " + sum);

 

[tranceport]

Originally posted by: Batman5177

Originally posted by: BA
In theory, this is how it works.(Of course this neglects the frequency, the case, etc)


Divide all the values by 10.
Raise 10 to the power of whatever you got
add all these up
Take the log
multiply by 10.

So in this case:
10^3.3=1995.3
10^2.1=125.89
10^3.5?=3162.3
10^3.1?=1258.9
------------------------
6542.4

log6542.4=3.82

3.82=38.2

38.2db

String fanNoise = " ";
int dbLevel = 0;
ArrayList list = new ArrayList();

while (!fanNoise.equals(null))
{
System.out.print("Enter fan db level ");
System.out.println();
fanNoise = console.readLine();

if (!fanNoise.equals(null))
{
dbLevel = Integer.parseInt(fanNoise);
list.add(dbLevel);
}

}

for (int i = 0; i < list.size(); i++)
{
list = list/10;
list = Math.exp(10,list);
}

int sum = 0;

for (int i = 0; i < list.size(); i++)
{
sum += int;
}

sum = Math.log(sum);

sum *= 10;

System.out.println("Answer: " + sum);

crack killz

 

[AtomicDude512]

Originally posted by: Batman5177

Originally posted by: BA
In theory, this is how it works.(Of course this neglects the frequency, the case, etc)


Divide all the values by 10.
Raise 10 to the power of whatever you got
add all these up
Take the log
multiply by 10.

So in this case:
10^3.3=1995.3
10^2.1=125.89
10^3.5?=3162.3
10^3.1?=1258.9
------------------------
6542.4

log6542.4=3.82

3.82=38.2

38.2db

String fanNoise = " ";
int dbLevel = 0;
ArrayList list = new ArrayList();

while (!fanNoise.equals(null))
{
System.out.print("Enter fan db level ");
System.out.println();
fanNoise = console.readLine();

if (!fanNoise.equals(null))
{
dbLevel = Integer.parseInt(fanNoise);
list.add(dbLevel);
}

}

for (int i = 0; i < list.size(); i++)
{
list = list/10;
list = Math.exp(10,list);
}

int sum = 0;

for (int i = 0; i < list.size(); i++)
{
sum += int;
}

sum = Math.log(sum);

sum *= 10;

System.out.println("Answer: " + sum);

Whoa. Can you give me something easier to understand?