- Aug 9, 2000
- 18,378
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I am trying to solve this differential equation. dy/dx=(x+y+3)^2.
It is not seperable, so you have to substitute.
Hence, v=x+y+3, in turn, y=-3-x+v.
This is where i am lost. I am looking at my notes and it says that this should lead to an equation dy/dx=1+v^2. HOw do i get to that equation?
edit: titile changed due to popular (2 people mentioned it) demand
It is not seperable, so you have to substitute.
Hence, v=x+y+3, in turn, y=-3-x+v.
This is where i am lost. I am looking at my notes and it says that this should lead to an equation dy/dx=1+v^2. HOw do i get to that equation?
edit: titile changed due to popular (2 people mentioned it) demand
