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Die size of GDDR5 modules

U

ultron

Member
I really wonder how many die size is required for GDDR5 chips to predict actual manufacturing costs. For example: Does doubling the storage size equal to die size? I searched and i never found any useful info about it.
 
Top fury x hbm; bottom r9 390x/290x gddr5
390X_Size_575px.jpg

On the 390x the vram is the 16 gray rectangles surrounding the white bordered square.
On the fury x it's the 4 rectangles on the inside of the square
HBM_7_Interposer_575px.png


memory chips tend to take up the same size, and the option is to either include more memory chips, or higher capacity memory. Current tech for GDDR5 is at 1GB (8 Gbit) chips, though it looks like the 390x uses 512MB chips.
390x: 16x32-bit= 512-bit bus; 512MB x 16 = 8GB.

some information and pictures of different examples of VRAM layout
http://www.playtool.com/pages/vramwidth/width.html (the playtool link has some outdated information, but is otherwise pretty informative)
http://www.techpowerup.com/forums/t...6-bit-etc-is-related-to-memory-amount.170588/
https://en.wikipedia.org/wiki/GDDR5_SDRAM

this thread has a rough breakdown for cost of parts of various GPUs from 2013
http://forums.anandtech.com/showthread.php?t=2302252
 
Last edited:
fralexandr:thanks for the reply but we still don't know the exact die size of these chips. We saw the package sizes on the board only. I saw Mercury Research's info but these were very old prices. (1,5 Gig GDDR5 is 27$ and this was too expensive)

@piroko thanks.
 
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