I really wonder how many die size is required for GDDR5 chips to predict actual manufacturing costs. For example: Does doubling the storage size equal to die size? I searched and i never found any useful info about it.
On the 390x the vram is the 16 gray rectangles surrounding the white bordered square.
On the fury x it's the 4 rectangles on the inside of the square
memory chips tend to take up the same size, and the option is to either include more memory chips, or higher capacity memory. Current tech for GDDR5 is at 1GB (8 Gbit) chips, though it looks like the 390x uses 512MB chips.
390x: 16x32-bit= 512-bit bus; 512MB x 16 = 8GB.
If both are manufactured on the same process, then yes. Two times the storage size needs two times the die size (since it needs two times the transistors).
fralexandr:thanks for the reply but we still don't know the exact die size of these chips. We saw the package sizes on the board only. I saw Mercury Research's info but these were very old prices. (1,5 Gig GDDR5 is 27$ and this was too expensive)
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