Definite proof that most of Digg readers are idiots

Toggle sidebar Toggle sidebar
halik

halik

Lifer
Oct 10, 2000
25,696
1
81
linky

this killed good 30 mins off my work day... funny proofs why 1 is not equal 0.999999 repeating
 
edro

edro

Lifer
Apr 5, 2002
24,326
68
91
It all comes down to whether or not you can describe .99... as a solid never changing entity. If you believe .99... is the same as .99..., then it equals 1.

If you believe that .99... is an idea or concept and not really an actual number, then no, it does not equal 1.
 
ultimatebob

ultimatebob

Lifer
Jul 1, 2001
25,134
2,450
126
Yeah... Digg should stick with things that they know, like drooling over the latest fake Apple rumor.
 
DannyLove

DannyLove

Lifer
Oct 17, 2000
12,876
4
76
I got one for you.... who gives a fvck.. i'm tired of seeing these threads regard .999=1 bla bla bla... SO WHAT! open the door, walk outside.... jesus!
 
S

Stuxnet

Diamond Member
Jun 16, 2005
8,392
1
0
You guys are arguing over symantics as they relate to their own specific contexts.

Does 1 = 0.99...?

Depends
 
J

j00fek

Diamond Member
Dec 19, 2005
8,099
1
0
Originally posted by: DannyLove
I got one for you.... who gives a fvck.. i'm tired of seeing these threads regard .999=1 bla bla bla... SO WHAT! open the door, walk outside.... jesus!
Click to expand...

:thumbsup:
 
C

Coolone

Senior member
Aug 18, 2001
983
0
0
Originally posted by: DannyLove
I got one for you.... who gives a fvck.. i'm tired of seeing these threads regard .999=1 bla bla bla... SO WHAT! open the door, walk outside.... jesus!
Click to expand...

QFT
 
K

KarmaPolice

Diamond Member
Jun 24, 2004
3,066
0
0
Hrmmm its been a while since I took calc...answer a question for me...

Limits....wouldnt .9999999 repeating be appraoching 1?


I am not going to try to say they are wrong...they are math people..i suck at math...but wondering.
 
Q

QED

Diamond Member
Dec 16, 2005
3,428
3
0
Originally posted by: KarmaPolice
Hrmmm its been a while since I took calc...answer a question for me...

Limits....wouldnt .9999999 repeating be appraoching 1?


I am not going to try to say they are wrong...they are math people..i suck at math...but wondering.
Click to expand...

Yes, but it doesn't "just approach" 1.. it is actually 1.

I think people are confusing the reprentation of a number with the number itself.

.99999999 and 1 are just two ways to represent the number we think of as 1.
 
F

fitzov

Platinum Member
Jan 3, 2004
2,477
0
0
Originally posted by: KarmaPolice
Hrmmm its been a while since I took calc...answer a question for me...

Limits....wouldnt .9999999 repeating be appraoching 1?


I am not going to try to say they are wrong...they are math people..i suck at math...but wondering.
Click to expand...

it approaches 1--it is not equal to 1. the only way I can think of (besides a simple logical proof) to prove it is by showing a graph of two functions--one whose range will go from .9 and approach 1 as it's domain increases while the other has a range of 1 for any domain.
 
Kyteland

Kyteland

Diamond Member
Dec 30, 2002
5,747
1
81
Originally posted by: KarmaPolice
Limits....wouldnt .9999999 repeating be appraoching 1?
Click to expand...
No, .99.... is a concrete number with an exact value. It doesn't approach anything. That's like asking if 2/3 approaches 4/6, or if 3 approaches pi. However, there are number of functions that define 0.99.... that do approach 1 the closer you get to infinity, like the sum of 9/10^x. Similarly, the sum 1-1/3+1/5-1/7+1/9... approaces pi/4 when taken to a large number of steps. When evaluated at infinity it is exactly pi/4.

The sum of 9/10^x is exactly equal to 1 when taken to infinity.
 
Kyteland

Kyteland

Diamond Member
Dec 30, 2002
5,747
1
81
Originally posted by: fitzov
Originally posted by: KarmaPolice
Hrmmm its been a while since I took calc...answer a question for me...

Limits....wouldnt .9999999 repeating be appraoching 1?

I am not going to try to say they are wrong...they are math people..i suck at math...but wondering.
Click to expand...
it approaches 1--it is not equal to 1. the only way I can think of (besides a simple logical proof) to prove it is by showing a graph of two functions--one whose range will go from .9 and approach 1 as it's domain increases while the other has a range of 1 for any domain.
Click to expand...
0.99... isn't a function, it is a concrete number. Its value doesn't fluctuate over time. There are functions that exist that approximate this number, and when taken to infinity they are exactly equal, but only when taken to infinty. The sum of 9/10^x approaches 1 as you increase x, but that function doesn't define 0.99... unless x is infinity. When x=infinty, the value of that function is 1.
 
Dumac

Dumac

Diamond Member
Dec 31, 2005
9,391
1
0
Originally posted by: Kyteland
Originally posted by: KarmaPolice
Limits....wouldnt .9999999 repeating be appraoching 1?
Click to expand...
No, .99.... is a concrete number with an exact value. It doesn't approach anything. That's like asking if 2/3 approaches 4/6, or if 3 approaches pi. However, there are number of functions that define 0.99.... that do approach 1 the closer you get to infinity, like the sum of 9/10^x. Similarly, the sum 1-1/3+1/5-1/7+1/9... approaces pi/4 when taken to a large number of steps. When evaluated at infinity it is exactly pi/4.

The sum of 9/10^x is exactly equal to 1 when taken to infinity.
Click to expand...

No. .99... isn't a exact value. It repeats infinately. It is like saying 9/10 + 9/100 + 9/1000 and so on. It never ends, but keeps on APPROACHING one. It becomes so close to one that it is arguably ok to ignore the diffference, but it is definately not the exact same number as 1.
 
You must log in or register to reply here.

TRENDING THREADS

COMPANY
RESOURCES
FOLLOW
Top Bottom