- Mar 30, 2001
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Crackrabbit's Super Geometry Thread!!!!!
- Thread starter CrackRabbit
- Start date
- Mar 30, 2001
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thanks ludacris
and the reason im running on 32mb of ram is because the 256mb dimm i had crapped out on me
and the reason im running on 32mb of ram is because the 256mb dimm i had crapped out on me
ok get the compass, put the sharp point on the vertex of the angle, set it to any radius you wish, and draw a semicircle
look at the points where the semicircle intercept the rays of the angle, place the sharp point of the compass on each interception point, draw another semicircle, repeat for the other point using a radius congruent to the one you used in the other point, connect the vertex to the intersection of the radii! voila, bisectors!
someone failed geometry
silverpig
Lifer
- Jul 29, 2001
- 27,703
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You never learned?
Put the compass at the corner of the angle. Draw an arc that extends through both rays. Then put the point of the compass at each of the intersections of that arc and your angle rays and draw a circle (fairly large). Draw a line with the straightedge from the corner of the angle and through both of the intersection points of the circles with each other. Done.
Still, you need a way to measure midpoints in order to bisect an angle.
Commonly what I would do is measure and mark the same distance on both arms of the angle (points A and B) and then draw a line AB. If the vertex of the original angle is C, then M, the midpoint of AB, bisects angle ACB. (Since ABC is isoceles)
But I can't think of a good way to do this with only a straight and a compass (and a pencil, implied). Can you?
Ohhhhhhh....
Well, hey, you learn something new every day.
No, I never learned that.
Now you've given me something interesting to do: write a proof that that actually does bisect the angle.
So I'd imagine the difficulty with trisecting comes from the fact that if you are to repeat this process you could divide the angle into quarters or eights but not thirds? Is that correct?
Well, hey, you learn something new every day.
No, I never learned that.
Now you've given me something interesting to do: write a proof that that actually does bisect the angle.
So I'd imagine the difficulty with trisecting comes from the fact that if you are to repeat this process you could divide the angle into quarters or eights but not thirds? Is that correct?
- Mar 30, 2001
- 16,642
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silverpig
Lifer
- Jul 29, 2001
- 27,703
- 12
- 81
If you want to do it using the midpoint of a line like that, then it's easy.
1. Draw your arc so it intersects the rays at A and B.
2. Draw line AB.
3. Place compass at A and draw a circle of radius r.
4. Repeat 3. for point B.
5. Call the intersections of circle A and circle B points C and D.
6. Draw line CD.
7. Label point M as the intersection of CD and AB.
8. M is the midpoint of AB as CD bisects it.
9. Draw a line from the origin of the angle O to point M. This line bisects angle AOB (if i can visualize this correctly it is colinear with line CD).
Just repeat it until there are 12 sections.....then 4 sections equal one thirdOriginally posted by: Alphathree33
Ohhhhhhh....
Well, hey, you learn something new every day.
No, I never learned that.
Now you've given me something interesting to do: write a proof that that actually does bisect the angle.
So I'd imagine the difficulty with trisecting comes from the fact that if you are to repeat this process you could divide the angle into quarters or eights but not thirds? Is that correct?
Of course, It would look really ugly, and take a while, but it works
EDIT: This does not work! I am Stupid!
you can go from 1/2 to 1/4, to 1/8, to 1/16 to 1/32 etc
If you are proficient in construction, you can get 5/8s, 3/4s, etc by copying angles and constructing them adjacent to each other
You cannot get 1/3! Thats like trying to add even numbers to get odd numbers
If you are proficient in construction, you can get 5/8s, 3/4s, etc by copying angles and constructing them adjacent to each other
You cannot get 1/3! Thats like trying to add even numbers to get odd numbers
- Mar 30, 2001
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Originally posted by: jjsole
alert: this thread has been hijacked. please proceed to the nearest exits one by one, quietly and peacefully, and no one will get hurt.
Damn Geometry Terrorists....
Originally posted by: SWirth86
Just repeat it until there are 12 sections.....then 4 sections equal one thirdOriginally posted by: Alphathree33 Ohhhhhhh.... Well, hey, you learn something new every day. No, I never learned that.
12 is not a power of 2 last time I checked.
You are correct. I am stupid.Originally posted by: Alphathree33
12 is not a power of 2 last time I checked.Originally posted by: SWirth86
Just repeat it until there are 12 sections.....then 4 sections equal one thirdOriginally posted by: Alphathree33 Ohhhhhhh.... Well, hey, you learn something new every day. No, I never learned that.
Whitecloak
Diamond Member
- May 4, 2001
- 6,074
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