- Apr 8, 2004
- 7
- 0
- 76
This is so far what I believe they are:
K7 = 9
K8 = 11
Pentium 4 / Pentium 4 Xeon / Itanium 2 = 6
Pentium M = 8
I am unsure about the Pentium M and even more unsure about the Itanium 2.
Any valued input is welcomed.
K7 = 9
K8 = 11
Pentium 4 / Pentium 4 Xeon / Itanium 2 = 6
Pentium M = 8
I am unsure about the Pentium M and even more unsure about the Itanium 2.
Any valued input is welcomed.