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could use some calc/precalc help...

Z

zixxer

Diamond Member
FULL EDIT:

I need some trig-related help. Simple stuff having to do with trig identities. Should take less than an hour. Please PM me, I'll pay $40 an hour.. should take about an hour.

 
dude...


1. We'll help you for free if you put forth some effort
2. put forth some effort, psot it, and we'll help you along or point out errors
3. AND FOR THE LOVE OF GOD PSOT AN IMAGE OF THE PROBLEM. NOTHING TICKS ME OFF MORE THAN ASTERICKS AND SLASHES....URGG ITS UNBEARABLE

🙂
 
To save you the trouble/money, the answer to the second one is 30 and 150 degrees.

Edit: see Goosemaster's post for more help
 
Originally posted by: Goosemaster
dude...


1. We'll help you for free if you put forth some effort
2. put forth some effort, psot it, and we'll help you along or point out errors
3. AND FOR THE LOVE OF GOD PSOT AN IMAGE OF THE PROBLEM. NOTHING TICKS ME OFF MORE THAN ASTERICKS AND SLASHES....URGG ITS UNBEARABLE

🙂
Click to expand...

haha awesome. Okay, I PM'ed you, and am going out for a couple hours. I'll have the review sheet scanned and uploaded then


thanks
 
Originally posted by: BigPoppa
Originally posted by: armatron
ok so lets start with #1?
Click to expand...

How about you post some of your work and we point you in the right direction?
Click to expand...

how about I seriously don't even know where to start man... I'm assuming I bring (2/7) over to the left side, ... for sin((pi/2)-x)-(2/7)


and then I'm about lost again
 
<-- pre-calc/calculus teacher

Memorize the following formulas:
cofunction identities example sin(pi/2 - x) = cos x
pythagorean identities, example sin^2(x) + cos^2(x) = 1
sum and difference formulas,
etc.

I'm at school; your site is blocked from here.
But, if this is for a calculus class and you're having trouble, I have one word for you:
Withdraw.
withdraw from the course or fail.
Take a lower level math class (that's pre-requisite for the class you're in.)
 
Sorry if that sounds harsh, but it's the truth. If you're in pre-calculus, and have the textbook in front of you, yet can't figure out
given sin (pi/2-x)=2/7 find cos x

find all the solutions in the interval [0,2pie): csc x - 2 = 0
Click to expand...

then you're in a world of trouble.

For the first problem, it's one of the identities. There's nothing to do. The answer is 2/7
sin(pi/2-x) EQUALS cos x

For the second problem, if you don't see that
cscx = 2
sin x = 1/2
(and what angles between 0 and 2pi have a sin value of 1/2? Hint: sin is positive in the 1st and 2nd quadrant. There are 2 answers.)

then you're in a world of trouble.
 
Oh, one last hint:
If you can do these problems if they were in degrees, but can't handle them in radians, then think in degrees.
Memorize pi/2, pi/3, pi/4, pi/6, etc. and their degree equivalents.
It's kinda like learning a foreign language - you translate the spanish to english, think about your reply in english, then translate your reply back to spanish before speaking it. I gave up on that battle years ago; it usually takes about a year of working in radians before my students seem to get really good at working in radians exclusively (without pauses)
 
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