suppose i tell you that my velocity is increasing at 2 km/sec for every kilometer traveled. what is the formula describing my acceleration in km/sec^2?
Assume:
V velocity at end of time interval t
Vo initial velocity
D distance traveled
K constant (in this case 2 km/sec)
is the following equation correct?
V=Vo + K*D
(i dont like the above equation because K*D does not have units of velocity)
anyway, going forward
D~Vaverage*t and Vaverage=(V+Vo)/2
so D~(V+Vo)*t/2
so substituting into the original equation:
V = Vo + KVt/2 + KVot/2
V - KVt/2 = Vo + KVot/2
V (1 - Kt/2) = Vo (1 + Kt/2)
V = Vo (1 + Kt/2) / (1 - Kt/2)
one then has to differentiate the above expression against time to get acceleration.
of course the flaw is the part where i approximate D~Vavg*t. I really should use an integral there but it's been 20 years since i've done that. i am sure this has been done before but i cant find a link on the net. Can anyone here point me in the right direction?
Assume:
V velocity at end of time interval t
Vo initial velocity
D distance traveled
K constant (in this case 2 km/sec)
is the following equation correct?
V=Vo + K*D
(i dont like the above equation because K*D does not have units of velocity)
anyway, going forward
D~Vaverage*t and Vaverage=(V+Vo)/2
so D~(V+Vo)*t/2
so substituting into the original equation:
V = Vo + KVt/2 + KVot/2
V - KVt/2 = Vo + KVot/2
V (1 - Kt/2) = Vo (1 + Kt/2)
V = Vo (1 + Kt/2) / (1 - Kt/2)
one then has to differentiate the above expression against time to get acceleration.
of course the flaw is the part where i approximate D~Vavg*t. I really should use an integral there but it's been 20 years since i've done that. i am sure this has been done before but i cant find a link on the net. Can anyone here point me in the right direction?
