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Chemistry...this is lame

You bumped after 5 min? 😕

In either case, you can't just convert between the two.
Hz is a frequency measurement, and eV is the measure of an electric charge.
 
how would i go about changing it to eV? trying to get 3.00 x 1016 hz to eV. thanks alot man

didnt think it would be such a direct conversion
 
You're not listening.

Without some type of prestated conversion factor, it is impossible to convert between the two.

WTF are you measuring the frequency of?

You need more info.
 
Originally posted by: Heen05
any idea how to go from 1.24 x 102 eV to kg? i hate this...damn these equations
Click to expand...

E=mc^2.

change eV to joules first.
 
What other info is stated in the problem? I've taken quite a few chem classes and have never heard of this type of conversion...

Edit: In minendo's link, it looks like it gives a relationship between energy and frequecy: E=hv
 
Now if your lab partner determined that there were 1.672 x 1019 atoms of H in an unknown sample of C2H4Cl2, how many milligrams would the unknown sample weigh?

any ideas? heh
 
Originally posted by: Heen05
Now if your lab partner determined that there were 1.672 x 1019 atoms of H in an unknown sample of C2H4Cl2, how many milligrams would the unknown sample weigh?

any ideas? heh
Click to expand...

That's just sad that you have to ask for help on a problem that easy...

Do your own homework. You obviously need the practice.
 
Come on, that one is completely straightforward. Count how many H atoms are in each molecule of dichloro-ethane (it's 4), use that ratio to figure out how many molecules of it you have based on the number of atoms in the sample, divide by Avogadro's #, and multiply by the molar mass.
 
Originally posted by: EarthwormJim
Originally posted by: Heen05
Now if your lab partner determined that there were 1.672 x 1019 atoms of H in an unknown sample of C2H4Cl2, how many milligrams would the unknown sample weigh?

any ideas? heh
Click to expand...

That's just sad that you have to ask for help on a problem that easy...

Do your own homework. You obviously need the practice.
Click to expand...

Exactly what I was thinking. This is hardly even chemistry, it's fractions and unit conversion.
 
Don't take this the wrong way, but you really need to review the material. You may even need to do extra homework beyond the assigned problems. You appear to be struggling and giving up way too easily.
 
Originally posted by: Heen05
Now if your lab partner determined that there were 1.672 x 1019 atoms of H in an unknown sample of C2H4Cl2, how many milligrams would the unknown sample weigh?

any ideas? heh
Click to expand...

You must be working on some very high level stuff if your lab can measure 1.672 x 1019 atoms. These questions obviously are too basic for the OP.
 
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