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Chemistry Question

bleeb

Lifer
You have two miscible liquids A and B distilled at 760 mmHg. At start, mole fraction of A is 90.0 and B is 10.0. At the end, the condensed vapor is mole fraction A is 15.0 and B is 85.0

what are the partial pressures of A and B?
what are the vapor pressures of pure A and B?
 
I had chemistry in my last semester. I have forgotten it by now.

Why not search and read up on partial pressure?
 
Originally posted by: asadasif
I had chemistry in my last semester. I have forgotten it by now.

Why not search and read up on partial pressure?

I have an answer, I just don't know if it's right because one of the pressures is huge.
 
here's a guess, haven't done this stuff in a long time

dalton's law
P=EPi, where Pi is equal toP=mi all in the gas phase
there Pa=760*.15 Pb =760*.85 Pa=114 Pb=646

raoult's law combined with dalton's
P=E(Pv*X)=EPi=> Pva*Xa=Pva*.9=Pa= 760*.15 => Pva=126.6 Pvb=6460

which if you think about seems right. B is a very small fraction of the liquid, yet it becomes a very large fraction of the gas, since the total pressure will be a function of the liquid fraction, then it must have a very large vapor pressure.
 
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