Hey guys..
Need some help with this question. Its more like a math question than a chem one.... Could you please verify if my solution is correct?
Q) I recently purchased a roll of aluminum foil for $1.59. The area of the roll as lisetd on the box is 6.96 square meters. I want to know specifically what I am getting for my money... Calculate the cost in dollars of a single aluminum atom in the roll of aluminum foil that I purchased today.
A) Density of Aluminum = 2700 kg/(m^(3)) = 2.7E6 g/m3
Since the thickness of the roll is probably negligible, I will take 6.96 to be the "volume of the roll" giving it the units m3.
Hence, (2.7E6)*(6.96) = 1.8792E7 g
Atomic mass of Aluminum = 26.98g
Therefore, No of moles = (1.8792e7g)/(26.98) = 6.965E5
Now, one mol of Al = 6.022E23 atoms
so, 6.965E5 mol of Al= x atoms
Therefore, X = 6.965E5 * 6.022E23 = 4.194418977E29 atoms
Cost= ($1.59)/(4.1944E29) = 3.79E-30 dollar/atom
Is that correct?
Thanks much..
Need some help with this question. Its more like a math question than a chem one.... Could you please verify if my solution is correct?
Q) I recently purchased a roll of aluminum foil for $1.59. The area of the roll as lisetd on the box is 6.96 square meters. I want to know specifically what I am getting for my money... Calculate the cost in dollars of a single aluminum atom in the roll of aluminum foil that I purchased today.
A) Density of Aluminum = 2700 kg/(m^(3)) = 2.7E6 g/m3
Since the thickness of the roll is probably negligible, I will take 6.96 to be the "volume of the roll" giving it the units m3.
Hence, (2.7E6)*(6.96) = 1.8792E7 g
Atomic mass of Aluminum = 26.98g
Therefore, No of moles = (1.8792e7g)/(26.98) = 6.965E5
Now, one mol of Al = 6.022E23 atoms
so, 6.965E5 mol of Al= x atoms
Therefore, X = 6.965E5 * 6.022E23 = 4.194418977E29 atoms
Cost= ($1.59)/(4.1944E29) = 3.79E-30 dollar/atom
Is that correct?
Thanks much..