CrazyPerson
Platinum Member
If you are given the following solutions (a and b), how would you prepare 500 mL of 0.200 M acetate buffer with a pH of 4.5? Please describe the procedure. Hint: Ka of acetic acid is 1.74 x 10-5
a. 1.00 M acetic acid
b. 1.00 M sodium acetate solution
a.
pka=-logka
ph=pka + log [conjugate base/weak acid]
4.5=4.76+log[0.2/x]
x=0.36
100 CH3COOH
180 CH3COO
220 H2O
b.
b is the same as a only
100 CH3CCH
180 CH3C00Na
220 H2o
a. 1.00 M acetic acid
b. 1.00 M sodium acetate solution
a.
pka=-logka
ph=pka + log [conjugate base/weak acid]
4.5=4.76+log[0.2/x]
x=0.36
100 CH3COOH
180 CH3COO
220 H2O
b.
b is the same as a only
100 CH3CCH
180 CH3C00Na
220 H2o
