can't solve this equation

[Sentinel]

err...derivatives.

4(pi)r - 32(pi)r^-2 = 0

all i need to find is ie. (x + 1) (x - 1)

pi ~ 3.14

trying to find the critical numbers so I can get max and min in f''(x)

 

[duragezic]

If you got r^-2 then multiply both sides of the equation by r^2 to get rid of it.

 

[Sentinel]

nice :thumbsup:

f'(x) = 4(pi)r(-8r^-1 + 1)

 

[Mrvile]

I don't get it.

4(pi)r - 32(pi)r^-2 = 0 ???

😕

 

[Sentinel]

the question is as follows:

a large soup can is to be designed so that the can will hold 16(pi) cubic inches of soup. Find the values of x and h such that the amount of metal needed is as small as possible.

the side requieres 2(pi)xh square inches of metal and each end requires (pi)x^2 square inches.

 

[ActuaryTm]

Too difficult. Math is hard.

 

[duragezic]

Originally posted by: Sentinel
nice :thumbsup:

f'(x) = 4(pi)r(-8r^-1 + 1)

What? Multiply both terms on the left from the original equation by r^2 and you get 4pir^3 for the first and the r^-2 cancels leaving you just -32pi as the 2nd term. Right-side is zero anyway.

 

[Sentinel]

yes but i need the max and min candidates

 

[Heisenberg]

Originally posted by: ActuaryTm
Too difficult. Math is hard.

Yeah really. All those numbers and variables and stuff. It's really stupid.

 

[hypn0tik]

Originally posted by: Heisenberg

Originally posted by: ActuaryTm
Too difficult. Math is hard.

Yeah really. All those numbers and variables and stuff. It's really stupid.

This coming from a guy whose username is 'Heisenberg'. Lol.

 

[ActuaryTm]

Originally posted by: hypn0tik
This coming from a guy whose username is 'Heisenberg'. Lol.

Try looking up the word "actuary".

Heisenberg's sarcasm may become a bit more apparent.