canned duster question

[NeoPTLD]

They sure are convenient way of blowing off dust from many different stuff and lasts a whole lot longer than a comparable sized can of compressed air.

Most uses pure difluoroethane and some uses pure tetrafluroethane and they both come in 10 ish oz.

Assuming you have a can of each type, I predict the difluoroethane type to provide more usage.

Gases at atm pressure and room temp occupies approximately 22.4 liters per mole.

difluoroethane has a molecular mass of 66.05g and each can contains 284g or 4.3moles. 4.3 x 22.4 =96.3 liters

teterafluoroethane has a molecular mass of 102g and each can also contains 284g. That's 2.78 moles or 62.4 liters.

I predict that you'll get 50% more use out of the cheaper, difluoroethane type. Is this right?

 

[fuzzynavel]

what suddenly made you come up with this??? LOL 🙂

What about the nozzle flow rate.......how do you know that the difluoroethane doesn't flow faster due to smaller molecular size etc.....They may both last exactly the same time!

also 284g of what is essentially a gas is an awful lot of gas......

I don't have a clue how much 10 ounces is.....I have been brought up metric.....About the size of a Pint glass??...just a little bit smaller!

 

[NeoPTLD]

Originally posted by: fuzzynavel


also 284g of what is essentially a gas is an awful lot of gas......

It all depends on the gas. You can calculate the moles of gas by taking the m.w. of compound in question over actual weight.

Once we know the # of moles, we can calculate the approximate gaseous state under normal pressure and temperature using the constant 22.4liters per mole.

The volume of 284g of 110g/mole fluorinated compound and the volume of 284g of 2g/mole H2 is a night and day difference.

I don't have a clue how much 10 ounces is.....I have been brought up metric.....About the size of a Pint glass??...just a little bit smaller!

10oz=284g