can someone point out what I am doing wrong in trying to use ASCII values in C?

[Onceler]

#include<stdio.h>
int main()
{
    FILE *fp;
fp=fopen("d:\\crypt.h", "w");

fprintf(fp, "char out[8];char cur[8];"
        "char con[255,255,255,255,255,255,255,255];/n"
        "if cur==con out==0,0,0,0,0,0,0,0;/n"
        "while(cur <= con) /n"
            "con=con-1/n"

            "if cur>=con out=out+1;");
         return 0;
}

I am trying to use the char array to store ASCII characters and to print them on the screen.
Thanks

 

[Ken g6]

 "char con[255,255,255,255,255,255,255,255];/n"

Wut? 😵

Did you mean:

 "char con[8]=[B]{[/B]255,255,255,255,255,255,255,255[B]}[/B];[B]\[/B]n"

If so, realize that you can only initialize an array this way. To change all the values to 0, for instance, you need a loop. (Or alternatively 8 separate statements in this case.)

Edit: Your ifs also need parentheses, and note the "\n", not "/n".
Edit2: Also, arrays are not initialized to anything in particular in C unless they're global. You should initialize all your arrays, either with a loop or as I did above.

 

[Onceler]

Thank you.
Any ideas on how I could self automate this to generate it's own code with what it is now provided? A human couldn't possibly go through all those numbers ever.

 

[Markbnj]

I think you might want to get to the point where you can output valid C code before you take it to the next step. In addition to the stuff Ken mentioned there are quite a few other basic syntax errors.

 

[Ken g6]

If you're looking to write a program inside a string, see also [post=35865342]this really nice macro[/post] that somebody came up with in a recent post in this forum. That might also help your syntax highlighter make syntax errors more obvious.