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Can anyone offer some math help?

Originally posted by: chuckywang
Integrate by parts


don't you need two terms for integration by parts?

example:

(e^x)*(x)dx


edit: so you'd need like x*sin(sqrt(x)) for it to work?
 
Originally posted by: Nab
Originally posted by: chuckywang
Integrate by parts


don't you need two terms for integration by parts?

example:

(e^x)*(x)dx


edit: so you'd need like x*sin(sqrt(x)) for it to work?

Your second term is just 1...I've done this exact integral before and I seem to recall you solve it by integration by parts.

You set u = sin(sqrt(x)) and dv = dx.

You could also try to set u = (2*sqrt(x)) and dv = sin(sqrt(x))/(2*sqrt(x)).
 
Originally posted by: chuckywang
Originally posted by: Nab
Originally posted by: chuckywang
Integrate by parts


don't you need two terms for integration by parts?

example:

(e^x)*(x)dx


edit: so you'd need like x*sin(sqrt(x)) for it to work?

Your second term is just 1...I've done this exact integral before and I seem to recall you solve it by integration by parts.

You set u = sin(sqrt(x)) and dv = dx.

You could also try to set u = (2*sqrt(x)) and dv = sin(sqrt(x))/(2*sqrt(x)).



oh yeah, brain fart @_@
 
You can always try using wolfram's integrator, do a search for "the integrator" and it will just give you the answer. It's pretty easy to reverse engineer a means for reaching your answer at that point, and then you won't forget in the future

Online integration tools FTW
 
Originally posted by: Nab
Originally posted by: chuckywang
Originally posted by: Nab
Originally posted by: chuckywang
Integrate by parts


don't you need two terms for integration by parts?

example:

(e^x)*(x)dx


edit: so you'd need like x*sin(sqrt(x)) for it to work?

Your second term is just 1...I've done this exact integral before and I seem to recall you solve it by integration by parts.

You set u = sin(sqrt(x)) and dv = dx.

You could also try to set u = (2*sqrt(x)) and dv = sin(sqrt(x))/(2*sqrt(x)).



oh yeah, brain fart @_@

I just did the integral...Ignore the first try. The second try is what gets you the correct answer.
 
Man that was a BlTCH, but I did it. Thanks for the right direction Chucky, and that's a cool site Nab. Definitely bookmarked it.
 
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