Hey.. Would really appreciate some help with the following calculus probs:
A) Find integral of : [(Sqrt(2x)*(e^(x))dx]^2
= (2x^2)(e^2x) dx
2*int((x^2)(e^2x))dx
I used u=e^2x , v'=x^2... I also tried u=x^2 but to no avail...
How do I solve this integral? i tried integration by parts but i seem to get approx the same integral and dunno how tosolve it..
B) Find the arc length of (((x/6)+2)^(3/2)) - 8
Formulated integral to be (Sqrt[1+((3/2)*((x/6+2)^(1/2)))^(2))])
And upon simplifying I got,
(1/Sqrt[24] ) * int (132+9x)
Is this correct?
Thanks much.
A) Find integral of : [(Sqrt(2x)*(e^(x))dx]^2
= (2x^2)(e^2x) dx
2*int((x^2)(e^2x))dx
I used u=e^2x , v'=x^2... I also tried u=x^2 but to no avail...
How do I solve this integral? i tried integration by parts but i seem to get approx the same integral and dunno how tosolve it..
B) Find the arc length of (((x/6)+2)^(3/2)) - 8
Formulated integral to be (Sqrt[1+((3/2)*((x/6+2)^(1/2)))^(2))])
And upon simplifying I got,
(1/Sqrt[24] ) * int (132+9x)
Is this correct?
Thanks much.
